Question #9daa9 Algebra Expressions, Equations, and Functions Variable Expressions 1 Answer Alan P. Oct 28, 2016 #color(green)(1/(a^2b+1))# Explanation: If we temporarily replace #a^2b# with #x# #(a^2b-1)/(a^4b^2-1) rarr (x-1)/(x^2-1)# We know that #x^2-1# can be factored as #(x-1)(x+1)# So #(x-1)/(x^2-1)= cancel(x-1)/((cancel(x-1))(x+1))=1/(x+1)# Restoring #x# back to #a^2b#, we have #color(white)("XXX")(a^2b-1)/(a^4b^2-1)= 1/(a^2b+1)# Answer link Related questions How do you write the variable expression for: a quotient of 2 and the sum of a number and 3 ? What are variables? What are variable expressions? How do you write variable expressions? How do you evaluate variable expressions? How do you simplify the expression #3x-x+4#? How do you write a quotient of a number and 6 as an expression? How do you evaluate the expression #2x+1# for #x=1#? How do you write a product of a number and 2 as an expression? How do you write 5 less than 2 times a number as a variable expression? See all questions in Variable Expressions Impact of this question 987 views around the world You can reuse this answer Creative Commons License