How do you find the perimeter of a rectangle, in simplest radical form, in which the base is $\sqrt{98}$ $sqrt98$ and the height is $5 \sqrt{2}$ $5sqrt2$ ?

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How do you find the perimeter of a rectangle, in simplest radical form, in which the base is $\sqrt{98}$ $sqrt98$ and the height is $5 \sqrt{2}$ $5sqrt2$ ?

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Answer 1 · 2016-10-29T14:03:48

34

Explanation:

$\sqrt{98} = 9.9$ $sqrt98 = 9.9$
$5 \cdot \sqrt{2} = 7.1$ $5*sqrt2 = 7.1$
Since two sides of the rectangle are 9.9 in length,
$2 \cdot 9.9 = 19.8$ $2*9.9 = 19.8$
Since the other two sides of the rectangle are 7.1 in length,
$2 \cdot 7.1 = 14.2$ $2*7.1 = 14.2$
Therefore, the total length of the perimeter of the rectangle is,
$19.8 + 14.2 = 34.0$ $19.8 + 14.2 = 34.0$

Answer 2 · 2016-10-29T14:19:58

The given rectangle has

$b a s e = \sqrt{98} = \sqrt{7^{2} \cdot 2} = 7 \sqrt{2}$ $base=sqrt98=sqrt(7^2*2)=7sqrt2$

and

$h e i g h t = 5 \sqrt{2}$ $height=5sqrt2$

So

$P e r i m e t e r = 2 (b a s e + h e i g h t) = 2 (7 \sqrt{2} + 5 \sqrt{2}) = 2 \cdot 12 \sqrt{2} = 24 \sqrt{2}$ $Perimeter=2(base +height)=2(7sqrt2 +5sqrt2)=2*12sqrt2=24sqrt2$

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How do you find the perimeter of a rectangle, in simplest radical form, in which the base is $\sqrt{98}$ $sqrt98$ and the height is $5 \sqrt{2}$ $5sqrt2$ ?

2 Answers

Explanation:

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