One x-intercept for a parabola is at the point (1,0). How do you use the factor method to find the other x- intercept for the parabola defined by this equation: #y=2x^2+8x-10#?

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Answer 1 · 2016-10-30T21:43:48

The second #x#-intercept is at #(-5, 0)#

The #x#-intercepts occur when #y = 0#.

#0 = 2x^2 + 8x - 10#

#0 = 2(x^2 + 4x - 5)#

#0 = x^2 + 4x - 5#

#0 = (x + 5)(x -1)#

#x = -5" AND " 1#

Hence, the x intercepts are at #(-5, 0)# and #(1, 0)#.

Hopefully this helps!