Question

How do you multiply `\frac { 1} { 7x } \cdot \frac { 27x ^ { 3} - 18x ^ { 2} } { 3x - 2}`?

Answer 1

This simplifies to `(9x)/7`.

Explanation:

Factor as much as possible.

`=1/(7x) xx (9x^2(3x - 2))/(3x - 2)`

`=1/(7cancel(x)) xx (9cancel(x^2)^xcancel(3x - 2))/(cancel(3x - 2)`

We are left with:

`=(9x)/7`

Hopefully this helps!