How do you solve the system of equations $-10x+8y=2$ and $-2x-4y=6$ by elimination?

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Answer 1 · 2016-11-01T08:48:35

$x=-1=y$

$-10x+8y=2$ $(i)$

$-2x-4y=6$ $(ii)$

So we have 2 equations in 2 unknowns, a system that is in principle solvable.

If I add $(i)+2xx(ii)$ , we get:

$-10x+8y-4x-8y=2+12$

i.e. $-14x=14$ ,

$x=(-14)/(14)=-1$

And, $y=-1$

How do you solve the system of equations -10x+8y=2-10x+8y=2 and -2x-4y=6-2x-4y=6 by elimination?