Question

How do you divide `\frac { x ^ { 2} - 2x - 8} { 3x - 12} \div \frac { x ^ { 2} - 4} { 9x ^ { 2} - 18x }`?

Answer 1

Switch into a multiplication:

`=>(x^2 - 2x - 8)/(3x - 12) xx (9x^2 - 18x)/(x^2 - 4)`

`=> ((x - 4)(x + 2))/(3(x- 4)) xx (9x(x - 2))/((x +2)(x - 2))`

`=>(cancel((x - 4))cancel((x + 2)))/(cancel((3))cancel((x - 4))) xx (cancel((9))^3xcancel((x - 2)))/(cancel((x + 2))cancel((x - 2)))`

`=> 3x`

Hopefully this helps!