Question

How do you write `-12x-2y>=42` in slope-intercept form?

Answer 1

Solve for `y`.

Explanation:

`-12x-2y>=42`

Add `12x` to both sides.

`-2y>=12x+42`

Divide both sides by `-2`.

`y>=(12x)/(-2)+42/(-2)`

Simplify.

`y>=-6x-21`

The graph will have a negative slope (-6) and the y-intercept is `-21`. Because this includes an `>=` symbol, a solid line will form the boundary, and the area to the right of the line will be shaded.

graph{y>=-6x-21 [-9.42, 10.58, -3.91, 6.09]}