How do you solve #2( x ^ { 2} - 7) = 6#?

1 Answer
A08
Nov 2, 2016

#x=+-sqrt10#

Explanation:

To solve
#2(x^2-7)=6#
Dividing both sides with #2#, we get
#(x^2-7)=3#
Keeping term containing #x# on LHS and taking other term to the other side we get
#x^2=3+7#
#=>x^2=10# Solving for #x# we get
#x=+-sqrt10#

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