How do you solve the system of equations #2x + 4y = - 12# and #5x + 2y = - 6#?

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Answer 1 · 2016-11-03T20:20:27

#(x,y)=(0,-3)#

#2x+4y=-12#
#5x+2y=-6#

To make the coefficient for both y terms equal, we multiply the second equation by 2.

#5x+2y=-6# |x2
#10x+4y=-12#

Subtract this equation from the first.

2x+4y=-12

#-(10x+4y=-12)#

After subtracting these equations we get:
#(2x-10x)+(4y-4y)=(-12+12)#

Simplify:
#-8x=0#
#x=0#

Substitute #x# back into one of the equations

#2(0)+4y=-12#
#4y=-12#
#y=-3#