How do you solve #-x^5+8x^4-15x^3=0# by factoring?

1 Answer
Noah G
Nov 4, 2016

#x = 0, 3 and 5#.

Explanation:

Factor out the GCF, #-x^3#, to begin with.

#-x^3(x^2 - 8x + 15) = 0#

To factor #x^2 - 8x + 15#, find two numbers that add to #-8# and that multiply to #15#. These two numbers are #-5# and #-3#.

#-x^3(x - 5)(x - 3) = 0#

#x = 0, 5, 3#

Hopefully this helps!

Related questions
Impact of this question
848 views around the world
You can reuse this answer
Creative Commons License