How do you differentiate y= log _3 x?

1 Answer
Nov 4, 2016

(dy)/(dx)=1/(xln3)

Explanation:

We can't directly derive logarithms with bases different to e, so we have to make this equation in terms of the natural log ln.

Using change of base, we can convert this to y=(lnx)/(ln3)

1/(ln3) is just a constant, and thus will not change.

(dy)/(dx)=1/(ln3)*1/x->the derivative of lnx is 1/x

=1/(xln3)