How do you determine whether the function #f(x) = -x^4-9x^3+2x+4# is concave up or concave down and its intervals?

1 Answer

#f(x)# is concave on #(-oo,-4.5)# and #(0,oo)#, and #f(x)# is convex on #(-4.5,0)#.

Explanation:

To find where a function is concave up, find where the second derivative of the function is positive.

#f(x)=-x^4-9x^3+2x+4#
Find #f'(x)#:
#f'(x)=-4x^3-27x^2+2#
Next, find #f''(x)#:
#f''(x)=-12x^2-54x#
#f''(x)=(-6x)(2x+9)#
Set #f''(x)# equal to zero to find inflection points
#0=(-6x)(2x+9)#
#x=0#, #x=-4.5#

After checking the signs of values around these numbers, we find that #f''(x)# is positive on #(-4.5,0)# i.e. convex and #f''(x)# is negative on #(-oo,-4.5)uu(0,oo)# i.e. concave.
graph{-x^4-9x^3+2x+4 [-10, 5, -1000, 1000]}