Question

What is the angular momentum of a rod with a mass of `5 kg` and length of `4 m` that is spinning around its center at `1 1 Hz`?

Answer 1

The angular momentum(L)=5526.4J-s.

Explanation:

Angular momentum `L=mr^2(omega)`
Here the object is rotated on its own centre, so we will be considering its length as radius.
As we know `omega=2xxpixxnu`
Substitute frequency value in above equation, we get `omega=69.08rad /sec`
Now substitute the angular velocity(`omega`) value in initial equation, we get `L= 5kg×16m^2×69.08rad /s`
`:. L=5526.4` Joules-sec