Question

How do you find the projection of u onto v given `u=<4, 2>` and `v=<1, -2>`?

Answer 1

`vecu` and `vecv` are perpendicular

Explanation:

The projection of `vecu` onto `vecv` is given by
`(vecu.vecv)/(∥vecv∥*∥vecv∥)vecv`
The dot product `vecu.vecv=〈4,2〉.〈1,-2〉=4-4=0`
Therefore `vecu` and `vecv` are perpendicular since the dot product `=0`
`:.` no projection is possible