Martha's mom is making party bags for all of her party guests, She has 24 green gumballs and 33 blue gumballs. If she wants to split them evenly between all the bags, without any leftovers, how many bags can she make?

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Answer 1 · 2016-11-04T22:31:05

Martha's mother can make #3# party bags, each with #11# blue gumballs and #8# green gumballs.

To answer this question, we must find the Greatest Common Factor of #24# and #33#. We will do this by looking at their prime factorizations.

#33 = 3 * 11#
#24 = 3 * 2 * 2#

The GCF of #33# and #24# is #3#, so Martha's mother can make #3# party bags, each with #11# blue gumballs and #8# green gumballs.