Question

A machine shop worker records the mass aluminum as 176 g. If one side of the cube measures 4 cm, what is the density of the aluminum?

Answer 1

`"Density"` `=` `"Mass"/"Volume"`, so...........

Explanation:

`rho_"Aluminum"` `=` `(176*g)/(4*cm)^3` `=` `2.76*g*cm^-3`.

This value seems to be consistent with the literature.