Question

How do you evaluate `log 900 - log 9`?

Answer 1

This can be simplified to `2`.

Explanation:

By the rule `log_a(n) - log_a(m) = log_a(n/m)`, we have:

`log900 - log9 = log(900/9) = log100`

Since the notation `loga` is a logarithm in base `10`, we can use the change of base formula to rewrite the following:

`=log100/log10 = log10^2/log10 = (2log10)/log10 = 2`

Hopefully this helps!