Question

How do you find the distance from the line with equation `y=9x-3` to the point at (-3,2)?

Answer 1

The answer is `32/sqrt82`

Explanation:

The distance from the point `(x_0,y_0)` to the line `ax+by+c=0`
is `d=(∣ax_0+by_0+c∣)/(sqrt(a^2+b^2))`
Here the line is `9x-y-3=0` and the point is `(-3,2)`

`:. d=(∣-27-2-3∣)/sqrt(81+1)=32/sqrt82`