What is the solution to #|4x-1|<=3#?

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Answer 1 · 2016-11-06T19:19:58

#x<=1#

You have to rearrange it but keep the #<=#

#4x<=4# (taking the #-1# over)

#x<=4/4#

#x<=1#

Answer 2 · 2016-11-06T20:35:55

#-1/2<=x<=1#

Solve #abs(4x-1)<=3#

There are two parts to this answer.

#color(red)(4x-1<=3)# and #color(blue)(4x-1>=-3)#

#color(red)(4x<=4)#

#color(red)(x<=1)#

#color(blue)(4x-1>=-3)#

#color(blue)(4x>=-2)#

#color(blue)(x>=-2/4)#

#color(blue)(x>=-1/2)#

#color(purple)(-1/2<=x<=1)#