How do you solve #2/3x-7=5#?
1 Answer
Nov 6, 2016
Explanation:
To eliminate the fraction, multiply all terms on both sides of the equation by 3.
#cancel(3)^1xx(2x)/cancel(3)^1-(3xx7)=(3xx5)#
#rArr2x-21=15# add 21 to both sides.
#2xcancel(-21)cancel(+21)=15+21#
#rArr2x=36# To solve for x, divide both sides by 2.
#(cancel(2) x)/cancel(2)=36/2#
#rArrx=18" is the solution"#
