Question

What is `(f/g)(-2)` when `f(x)=4x-6` and `g(x) = 4x^2+14x+2`?

Answer 1

`(f/g)(-2) = 5/17`

Explanation:

`(f/g)(x) = (4x - 6)/(4x^2 + 14x + 2)`

`(f/g)(x) = (2(x - 3))/(2(x^2 + 7x + 1))`

`(f/g)(x) = (x- 3)/(x^2 + 7x + 1)`

`(f/g)(2) = (-2 - 3)/(-2^2 - 14 + 1)`

`(f/g)(2) = (-5)/(-17)`

`(f/g)(2) = 5/17`