Question

How do you solve `log_3 (8)+log_3(-5x)=3`?

Answer 1

`x=-27/40`

Explanation:

`x<0` to make `log_3(-5x)` real.

Use log (ab) = log a + log b.

`log_3(-40x)=3`.

Inversely,

`-40x=3^3=27`, and so,

`x=-27/40`.