Question

What is the molarity of `NO_3^-` in each solution?

0.150 M `KNO_3`
0.150 M `Al(NO_3)_3`

Answer 1

For `"potassium nitrate"`, clearly `[NO_3^-]=0.150*mol*L^-1`........

Explanation:

For `"aluminum nitrate"`, clearly `[NO_3^-]=3xx0.150*mol*L^-1=0.450*mol*L^-1`........because `"aluminum nitrate"` ionizes to give 3 equiv of nitrate anion.