How do you multiply #((3, -2), (-1, 1))# with #((3, 1), (-2, 4))# with #((-2, 4), (1, 3))#?

1 Answer
Narad T.
Nov 10, 2016

The answer is #=((-31,37),(13,-11))#

Explanation:

The product of two 2x2 matrices is
#((a,b),(c,d))*((e,f),(g,h))=((ae+bg,af+bh),(ce+dg,cf+dh))#

#((3,-2),(-1,1))((3,1),(-2,4))=((9+4,3-8),(-3-2,-1+4))#

#((13,-5),(-5,3))#

and the second multiplication is

#((13,-5),(-5,3))*((-2,4),(1,3))=((-26-5,52-15),(10+3,-20+9))#

#((-31,37),(13,-11))#

Related questions
See all questions in Multiplication of Matrices
Impact of this question
1771 views around the world
You can reuse this answer
Creative Commons License