Which quadrant does the given angle 621 degrees lie?

1 Answer
Nov 11, 2016

#Q_3#

Explanation:

If I remember correctly, this was my way of finding the Q of any

#theta^o#:

Let q = int ( #theta/90# ) be the quotient from the division

#theta/90#.

If q is even and a multiple of 4, #theta in Q_1#;

otherwise #theta in Q_3#.

If q is odd and the remainder in ( q/4 ) is 1, #theta in Q_2#;

otherwise #theta in Q_4#.

Here, int ( 621/90 ) = 6 that is even but not a multiple of 4.

So, #621^o in Q_3#.

For that matter, int ( 711/90 )= 7 that is odd but not a multiple of 3. So,

#711^o in Q_4#,

Int ( 801/80 )= 8 that is even but a multiple of 4. So, #801^o in Q_1#

Int (891/80)= 9 that is odd but a multiple of 3. So, #891^o in Q_2#

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