Question

Question #30ae8

Answer 1

The distance is `=625 m`

Explanation:

Let's convert the `kmh^(-1)` in `ms^(-1)`

`90kmh^(-1)=90*1000/3600=900/36=25 ms^(-1)`

We use the equation,

`v^2=u^2+2as`
where `v=`final velocity (`0`)
`u=` initial velocity (`25ms^(-1)`)
`a=` acceleration (`-0.5ms^(-2)`)
`s=` distance `=?`

So, `0=25^2+(2*-0.5*s)`

`s=25^2=625 m`