Question

How do you evaluate `cos ^ -1 (- sqrt3/2)`?

Answer 1

`x=(5pi)/6, x=(7pi)/6`

Explanation:

Use the unit circle, and find where cosine is equal to `(-sqrt3/2)`

`cos^-1(-sqrt3/2) = x`
`cosx=-sqrt3/2`
`x=(5pi)/6, x=(7pi)/6`