Question

If `p(x)` has a minimum value of `(-8)` and x-intercepts at `x=-4` and `x=-2/3`, for what values of `x` is `p(x) <=0`?

Answer 1

`x in [-4,-2/3]`

Explanation:

I made the assumption that you intended the second intercept to be `(-2/3,0)`
also, since this was asked under Quadratic Equations, I have assumed that `p(x)` is a quadratic equation.

If these assumptions are true then
since `p(x)` has a minimum value of `p(x)=-8`
with intercepts (where `p(x)=0`) of `x=-4` and `x=-2/3`
then
`color(white)("XXX")p(x) <=0` when `x` is between `(-4)` and `(-2/3)` inclusive.

[Ask as a separate question if you need the derivation of the exact formula for `p(x)`].