How many moles of sodium carbonate contain #1.773 xx 10^17# carbon atoms?

1 Answer
Truong-Son N.
Nov 12, 2016

If we want #1.773xx10^17# #"C"# atoms in #"Na"_2"CO"_3#, then we can define our own ratio of:

#"1 mol C" = "1 mol Na"_2"CO"_3#

Therefore:

#color(blue)(1.773xx10^17 "C atoms") xx ("1 mol C")/(6.022xx10^23 "C atoms") xx ("1 mol Na"_2"CO"_3)/("1 mol C")#

#= color(blue)(2.944xx10^(-7) "mols Na"_2"CO"_3)#

Related questions
See all questions in The Mole
Impact of this question
25724 views around the world
You can reuse this answer
Creative Commons License