Question

What is the vertex and axis of symmetry of the graph of `f(x)=x^2+4x+3`?

Answer 1

Vertex `(-2 , -1),` axis of symmetry is `x= -2`

Explanation:

Use completing the square to rewrite function as

`f(x) = (x +2)^2 +3 - 4`

`= (x +2)^2 - 1`

Vertex is when `x =-2` because then `(x+2)^2 = 0`
and the minimum value is `-1`

The axis of symmetry can also be found from using:

`x =(-b)/(2a)`