Question

What is the formula weight of silver chromate `(Ag_2CrO_4)` in amu?

Answer 1

The formula weight for `"Ag"_2"CrO"_4"` is `"331.728 u"`.

Explanation:

In order to determine the formula weight of a compound, multiply the atomic weight on the periodic table of each element by its subscript and add the results.

Compound: silver chromate
Formula Unit: `"Ag"_2"CrO"_4"`

`(2xx"107.868 u Ag")+(1xx"51.9961 u Cr")+(4xx"15.999 u O")="331.728 u"`