How do you find the sum of the infinite geometric series given #1/4+1/6+2/18+ ...#?

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Answer 1 · 2016-11-13T04:57:02

The sum is #3/4#.

Use the formula #s_oo = a/(1 - r)#, where #r = t_2/t_1#.

#r = t_2/t_1#

#r = (1/6)/(1/4) = 1/6 xx 4 = 2/3#

#:.s_oo = (1/4)/(1 - 2/3)#

#s_oo = (1/4)/(1/3)#

#s_oo = 3/4#

Hopefully this helps!