How do you solve #log_9x=2#?

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Answer 1 · 2016-11-13T17:11:47

#log_9 x = 2#

Use the log rule: If #log_b x= a#, then #b^a=x#

#9^2=x#

#x=81#

Answer 2 · 2016-11-13T17:12:36

#x=81#

From definition of logarithm

if #a^m=b# then #log_a b=m#

and vice versa i.e. if #log_a b=m# then #a^m=b#

Hence #log_9 x=2# implies #9^2=x#

i.e. #x=81#