How do you find the sum of the series #i# from i=1 to 18?
1 Answer
Nov 13, 2016
# sum_(i=1)^18 i = 171 #
Explanation:
Using the standard results:
We have;
# sum_(i=1)^18 i = 1/2(18)(18+1) #
# :. sum_(i=1)^18 i = 1/2(18)(19) #
# :. sum_(i=1)^18 i = 171 #
