Question

Question #c6f97

Answer 1

`3.83`[m/s]

Explanation:

The giration radius is given by

`r = l costheta`

The acceleration induced by the rotational movement is

`vec a_r = (omega^2r) hat i = v^2/r hat i`

Considering a noninertial rotating reference frame. In equilibrium, the weigth `-m g hat j` and the centrifugal force `m (v^2/ r) hat i` have null momentum sum concerning the hanging cable fulcrum.

`M_0 = (l sintheta)(m v^2/r)-(l costheta)(m g) = 0`

then

`v=sqrt(cos^2theta/sintheta l g) approx 3.83`[m/s]