How do you name #"CH"_3"Br"#?
1 Answer
Nov 14, 2016
Well, you need to know what the name of the alkyl chains are, and the stem for the substituent.
- Alkyl groups are chains of
#"CH"# bonds, such as#"H"_3"C"-("CH"_2)_n-# .
The most common ones are:
#"Meth"-# : one carbon in the main chain
#"Eth"-# : two carbons in the main chain
#"Prop"-# : three carbons in the main chain
#"But"-# : four carbons in the main chain
#"Pent"-# : five carbons in the main chain
#"Hex"-# : six carbons in the main chain
#"Hept"-# : seven carbons in the main chain
#"Oct"-# : eight carbons in the main chain
#"Non"-# : nine carbons in the main chain
#"Dec"-# : ten carbons in the main chain
- Substituents are non-hydrogens, such as
#-"Br"# ,#-"Cl"# ,#-"OH"# ,#-"NH"_2# , etc. They each have their own stems, such as bromo, chloro, hydroxyl, or amino, in that order.
You have at least two ways you can name
- Bromo + meth + ane, because a bromine substituent (bromo) is on a one-carbon alkyl chain (meth-), and the alkyl chain has no double or triple bonds (making it a haloalkane compound, specifically a bromoalkane compound, as compared to a bromoalkene or a bromoalkyne).
- Meth + yl brom + ide, because the one-carbon chain has the prefix "meth-", the "yl" is for hydrocarbon chains that are not terminated on the second end by a
#"CH"_3# , and bromide is the name of the#"Br"^(-)# anion.
So, two possible names are bromomethane or methyl bromide.
