How do you simplify #12^2-[20div2+5(6+1)]#?

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Answer 1 · 2016-11-14T09:55:33

#99#

Identify the different terms first.
Each term will simplify to a single answer and these will be added or subtracted only in the last line.

Within each term, the order of operations is:

-Brackets,
-powers and roots,
-multiply and divide

There are 2 terms. but inside the bracket there are also 2 terms.

#color(blue)(12^2) -[color(red)(20div2)color(purple)(+5(6+1))]#

#=color(blue)(144) -[color(red)(10)color(purple)(+5(7))]#

#=color(blue)(144) -[color(red)(10)color(purple)(+35)]#

#=color(blue)(144) -45#

#=99#