Question

What is the acceleration of a 6.4 kilogram bowling ball if a force of 12 N is applied to it?

Answer 1

The acceleration of the bowling ball is `1.875` `m/s^2`.

Explanation:

The formula we will use is based off of Newton's Second Law is `F_"NET"` = `m` `a`. Where:
=> the net force is in Newtons (`N`).
=>`m` is mass in kilograms (`kg`).
=>`a` is acceleration in `m/s^2`.

The `F_"A"` is `12N` `"[forward]"`, therefore we know the net force is not `0`. Normally, `F_"F"` is considered, but we do not have enough information to calculate it, so we will assume a frictionless problem.

If the only force is the applied force, then the net force is `12` `N`. Knowing this and the mass, we can isolate and solve for `a`.

`F_"NET"` = `m` `a`

`12 = 6.4` `a`

`1.875 =` `a`

Therefore, the acceleration of the bowling ball is 1.875`m/s^2`.

Hope this helps :)