How do you solve #\frac { b + 6} { b - 3} = 2#?

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Answer 1 · 2016-11-15T02:59:17

#b=12#

Multiply both sides by #b-3#.

#b+6=2(b-3)#

Distribute the 2

#b+6=2b-6#

Add #6# to both sides

#b+12=2b#

Subtract #b# from both sides

#12=b#