Question #ead50

2 Answers
Nov 15, 2016

The point #(-4,0)#

Explanation:

#x# intercept is when #y=0#

substitute #0# instead of #y# and then solve for #x#

#-3x+8(0)=12#
#-3x=12#
#x=-4#

The point is #(-4,0)#

Nov 15, 2016

The x-intercept= -4
#(-4,0)#

Explanation:

To find the x-intercept of a graph, make #y=0#

#-3x+8y = 12#

#-3x+8(0) = 12#

#-3x= 12" "larrdiv -3#

#x =-4#