Question #ead50

Question

1356 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-15T15:24:19

The point #(-4,0)#

#x# intercept is when #y=0#

substitute #0# instead of #y# and then solve for #x#

#-3x+8(0)=12#
#-3x=12#
#x=-4#

The point is #(-4,0)#

Answer 2 · 2016-11-15T15:25:44

The x-intercept= -4
#(-4,0)#

To find the x-intercept of a graph, make #y=0#

#-3x+8y = 12#

#-3x+8(0) = 12#

#-3x= 12" "larrdiv -3#

#x =-4#