How do you simplify #2\times \frac{2}{9}+2\times \frac{5}{6#}?

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Answer 1 · 2016-11-16T04:29:01

#2xx2/9+2xx5/6=2 1/9#

Using distributive property of numbers

#2xx2/9+2xx5/6#

= #2xx(2/9+5/6)#

Now as GCD of denominators (or divisors) is #18#, we can write this as

#2xx((2xx2)/(9xx2)+(5xx3)/(6xx3))#

= #2xx(4/18+15/18)#

= #2xx19/18#

= #cancel(2)^1xx19/(cancel(18)^9)#

= #19/9#

= #2 1/9#

Answer 2 · 2016-11-16T08:12:20

#2 1/9#

Simplify each term by multiplying the fractions:

#2/1xx2/9 + cancel2/1 xx5/cancel6^3" "larr# cancel if possible

=#4/9 +5/3" "larr# addition of fractions

#color(white)(xxxxxxxxxxxxxxxxxxxxxxx)5/3 xx3/3 = 15/9#

=#(4+15)/9" "larr# convert to a common denominator

=#19/9#

=#2 1/9#