Question

An object with a mass of `2 kg` is moving at `5 m/s` over a surface with a kinetic friction coefficient of `2`. How much power will it take to accelerate the object at #8 m/s^2?

Answer 1

The power required to accelerate the object at `8m//s^2` is 90Watts.

Explanation:

Power is also defined as the product of force and velocity.
`=>P = Fxxv`
Now we have to find out force value as velocity value is already given.
This case is taken as Motion of block on a rough fixed horizontal surface.
Here the force is defined `F= ma+f_k`.
Now substitute this force in above power definition, we get
`=>P=(ma+f_k)v`
By substituting the given numerical values
`=>P=[2kg(8m//s^2)+2]xx5m//s`
`:.P=90`Watts.