Question

Question #49284

Answer 1

`1- (sin^2x/(1+cosx) + (1+cosx)/sinx - sinx/(1-cosX))`

`=1-(((1-cosx)(1+cosx))/(1+cosx)+(1+cosx)/sinx-(sinx(1+cosx))/((1-cosx)(1+cosx)))`

`=1-1+cosx-(1+cosx)/sinx +(sinx(1+cosx))/(1-cos^2x)`

`=cosx-(1+cosx)/sinx +(sinx(1+cosx))/sin^2x`

`=cosx-(1+cosx)/sinx +(1+cosx)/sinx`

`=cosx`