Question

How do you factor given that `f(-5)=0` and `f(x)=4x^3+9x^2-52x+15`?

Answer 1

We know that `-5` is a factor by the remainder theorem. We divide `4x^3 + 9x^2 - 52x + 15` by `x + 5`:

So, our current factoring is `(x + 5)(4x^2 - 11x + 3)`.

`4x^2 - 11x + 3` cannot be factored any further, so this is as far as we can go.

Hopefully this helps!