Question

How do you complete the square `f(x)=x^2+6x-3`?

Answer 1

`f(x)= 1(x^2 + 6x + m - m) - 3`

`m = (b/2)^2 = (6/2)^2 = 9`

`f(x) = 1(x^2 + 6x + 9 - 9) - 3`

`f(x) = 1(x + 3)^2 - 9 - 3`

`f(x) = (x + 3)^2 - 12`

Hopefully this helps!