For #f(t)= (t^2,t^3)# what is the distance between #f(1)# and #f(3)#?
1 Answer
Nov 18, 2016
Explanation:
By Pythagoras, the distance,
# d^2 = (27-1)^2 + (9-1)^2 #
# :. d^2 = 26^2 + 8^2 #
# :. d^2 = 676 + 64 #
# :. d^2 = 740 #
# :. d = sqrt(740) ~~ 27.2#