How do you solve #-2x + 16\leq 35- 16#?

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Answer 1 · 2016-11-19T13:59:08

#x >= -3/2#

Perform the necessary mathematics to isolate and solve for #x# while keeping the inequality balanced.

First, subtract 16 from each side of the inequality:

#-2x + 16 - 16 <= 35 - 16 - 16#

#-2x + 0 <= 35 - 32#

#-2x <= 3#

Next divide each side by #-2#. Because we are multiplying or dividing by a negative number the inequality needs to be reversed:

#(-2x)/-2 >= 3/(-2)#

#1x >= -3/2#

#x >= -3/2#