How do you solve #x+ 3= - 11- x#?

1 Answer
Nov 19, 2016

#x=-7#

Explanation:

#x+3=-11-x#
Add #x# to both sides #\rArrx+3\color(olive)(+x)=-11\cancel(-x)\cancel(\color(olive)(+x))#
Subtract 3 from both sides #rArr2x\cancel(+3)\cancel(\color(indianred)(-3))=-11\color(indianred)(-3)#
Simplify #rArr2x=\color(mediumaquamarine)(-14)#
Divide both sides by 2 #rArr(\cancel(2)x)/\cancel(\color(seagreen)(2))=-14/\color(seagreen)(2)#
#x=-7#

plug in to check:
#\color(red)(-7)+3\stackrel{?}{=}-11-(\color(red)(-7))#
#-4=-4#