How do you solve #c/sin60=3/sin75#?
1 Answer
Nov 20, 2016
Explanation:
The first step is to
#color(blue)"cross-multiply"#
#rArrcxxsin75^@=3xxsin60^@# To solve for c, divide both sides by
#sin75^@#
#(c cancel(sin75^@))/cancel(sin75^@)=(3sin60^@)/sin75^@#
#rArrc=(3sin60^@)/sin75^@#
#=2.69" to 2 decimal places"#